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dBu to dBV Converter (dBu / dBV / dBm & Volts)

This dBu to dBV converter moves between dBu, dBV, dBm and volts RMS in real time. Type a value in any field and the others update instantly. Because dBm depends on load impedance, pick the impedance used for the dBm relationship (600 Ω classic audio, 50 Ω or 75 Ω RF, or a custom value). dBu and dBV always sit a fixed 2.2185 dB apart; dBm only equals dBu at 600 Ω.

Enter Any Value

dBu
0 dBu = 0.7746 V; +4 dBu = pro line level
dBV
0 dBV = 1.0 V; −10 dBV = consumer line level
dBm
Depends on impedance below; 0 dBm = 1 mW
V
RMS volts — the common quantity all three dB units reference
Impedance for dBm relationship

Result

Level (dBu)
ref 0.7746 V RMS
dBu
dBV
dBm
Vrms
Power into selected Ω
Formulas
dBV = 20·log10(Vrms / 1.0)
dBu = 20·log10(Vrms / 0.7746)
dBm = 20·log10(Vrms) − 10·log10(R) + 30
dBu = dBV + 2.2185 dB (fixed); dBm = dBu only at R = 600 Ω

Common Level Reference

LeveldBudBVVrmsNotes
0 dBu reference0 dBu−2.218 dBV0.7746 V= 0 dBm into 600 Ω (historical origin of dBu)
0 dBV reference+2.218 dBu0 dBV1.0 V1 volt RMS reference
Pro line level (+4 dBu)+4 dBu+1.78 dBV1.228 VBalanced studio / broadcast nominal level
Consumer line level (−10 dBV)−7.78 dBu−10 dBV0.3162 VUnbalanced −10 dBV gear (hi-fi, consumer)
0 dBm into 600 Ω0 dBu−2.218 dBV0.7746 V1 mW dissipated in 600 Ω
0 dBm into 50 Ω−10.79 dBu−13.01 dBV0.2236 V1 mW dissipated in 50 Ω (RF reference)

The dBu and dBV columns above are fixed (impedance-independent). The dBm equivalents shown in the calculator depend on the impedance you select.

About dBu, dBV & dBm Levels

dBu and dBV are voltage decibel scales: they describe an RMS voltage relative to a fixed reference, with no impedance needed. dBV references 1 volt RMS (dBV = 20·log10(V/1)). dBu references 0.7746 volts RMS (dBu = 20·log10(V/0.7746)). That odd-looking 0.7746 V is exactly √(0.001 W × 600 Ω) — the voltage that dissipates 1 milliwatt in a 600 Ω load. Historically that is why 0 dBu was defined to equal 0 dBm into 600 Ω. Because both scales use the same 20·log10 form, the gap between them is a constant: dBu = dBV + 2.2185 dB, regardless of the signal level. To convert dBu to volts directly, reverse the log: V = 0.7746 × 10^(dBu/20); to go the other way (dBV to dBu), simply add 2.2185.

Why dBm is different (it needs an impedance)

dBm is a power unit: 0 dBm = 1 milliwatt. To turn a voltage into a power you must know the load resistance, because P = Vrms² / R. So dBm = 10·log10(P/0.001) = 20·log10(Vrms) − 10·log10(R) + 30. The same voltage produces a different dBm depending on whether it drives 600 Ω, 50 Ω, or 75 Ω. This dBm to volts calculator reverses that relationship: pick the impedance, enter a dBm figure, and get the RMS voltage directly. This makes the impedance explicit so the dBm figure is never ambiguous. The classic audio value is 600 Ω; RF systems use 50 Ω (most radio gear) or 75 Ω (video, antenna feeds).

dBm only equals dBu at 600 ohms

The convenient identity "0 dBu = 0 dBm" is true only when the impedance is 600 Ω, because 0.7746 V across 600 Ω dissipates exactly 1 mW. At any other impedance the equality breaks: 0 dBu (0.7746 V) into 50 Ω is +10.79 dBm, and into 75 Ω it is +9.03 dBm. Modern audio gear is almost always voltage-driven into high-impedance inputs (10 kΩ or more), so almost no power is actually transferred — which is exactly why pro audio uses the impedance-free dBu and dBV for level and reserves dBm for cases where real power into a known load matters.

Pro (+4 dBu) vs consumer (−10 dBV) line level

Two nominal line levels dominate audio. +4 dBu (about 1.228 V RMS) is the balanced "professional" nominal level used in studios and broadcast. −10 dBV (about 0.316 V RMS) is the unbalanced "consumer" level used in hi-fi and prosumer gear. The headline difference is about 11.78 dB, not a round 14 dB, precisely because one is referenced to dBu and the other to dBV: +4 dBu = +1.78 dBV, and +1.78 dBV − (−10 dBV) = 11.78 dB. (You will often see it rounded to "11.8 dB" or quoted as "about 12 dB.") Interfacing the two without gain staging is a common cause of either weak, noisy signals or clipping. This tool functions as both a pro audio level converter and a line level converter — useful anywhere you need to reconcile the +4 dBu professional standard with the −10 dBV consumer standard.

Frequently Asked Questions

How do I convert dBu to dBV?
Add a fixed offset: dBV = dBu − 2.2185 dB, and dBu = dBV + 2.2185 dB. The offset is constant because both scales are 20·log10 of voltage; only the reference differs (0.7746 V for dBu, 1.0 V for dBV). For example, +4 dBu = +1.78 dBV, and 0 dBV = +2.22 dBu. No impedance is needed for this conversion.
How do I convert dBu or dBV to volts?
Reverse the log: Vrms = 0.7746 × 10^(dBu/20) for dBu, and Vrms = 1.0 × 10^(dBV/20) for dBV. So 0 dBu = 0.7746 V, +4 dBu = 1.228 V, 0 dBV = 1.0 V, and −10 dBV = 0.316 V. The voltage field in the calculator above does this automatically and updates the other units live.
Why does dBm need an impedance but dBu and dBV do not?
dBm measures power (0 dBm = 1 mW), and turning a voltage into power requires the load resistance: P = Vrms² / R. dBu and dBV measure voltage directly, so no impedance is involved. That is why this tool asks you to choose the impedance only for the dBm relationship, and states the assumed value (600, 50, 75, or custom ohms) wherever it shows a dBm figure.
Is 0 dBu the same as 0 dBm?
Only at 600 Ω. 0 dBu is defined as 0.7746 V RMS, which dissipates exactly 1 mW (0 dBm) in a 600 Ω load — that is the historical origin of the dBu reference. At any other impedance they differ: 0 dBu into 50 Ω is about +10.79 dBm, and into 75 Ω about +9.03 dBm. The calculator shows the impedance assumption next to every dBm value.
What is the formula for dBm from a voltage?
dBm = 10·log10(P / 0.001), where P = Vrms² / R. Expanded, that is dBm = 20·log10(Vrms) − 10·log10(R) + 30. The +30 converts the 1 W natural reference down to the 1 mW dBm reference (10·log10(1000) = 30). Choose R to match your system: 600 Ω for classic audio, 50 Ω or 75 Ω for RF.
What is the difference between +4 dBu and −10 dBV line level?
+4 dBu (the balanced pro level) is about 1.228 V RMS; −10 dBV (the unbalanced consumer level) is about 0.316 V RMS. Converted to a common scale, +4 dBu = +1.78 dBV, so the difference is +1.78 − (−10) = 11.78 dB, not a round 14 dB. The mismatch in references (dBu vs dBV) is why the gap is the awkward ~11.8 dB figure.
Why is the dBu reference 0.7746 volts?
It is √(0.001 W × 600 Ω) = √0.6 ≈ 0.7746 V — the RMS voltage that delivers 1 milliwatt into a 600 Ω load. Early telephone and broadcast audio used 600 Ω lines and a 1 mW (0 dBm) reference, so engineers picked the matching voltage as the 0 dBu point. The "u" stands for "unloaded" (or "unterminated"), signalling that dBu is a pure voltage reference even though its value came from a 600 Ω power calculation.
Do modern audio inputs actually dissipate the dBm power shown?
Usually not. Contemporary gear is voltage-driven into high-impedance inputs (often 10 kΩ or more), so very little power is transferred — the meaningful quantities are the dBu and dBV voltage levels. The dBm value here is the power that would be dissipated if the signal drove the selected impedance, which is most relevant for true 600 Ω terminated audio lines or 50/75 Ω RF systems. Treat the dBm figure as conditional on that impedance assumption.